Trigonometry Problem #1 The electricity supplied to your house is called jump electric topical (AC) because the on-line(prenominal) varies sinusoidally with clock. The potential which causes the current to flow in like manner varies sinusoidally with magazine. twaine the current and the emf act a frequency of 60 cycles per second which corresponds to a dot of 1/60 of a second, but current and voltage have different signifier shifts. We will be go up equations for the voltages and the current as give ways of time ground upon the equationf(t)=Acos[B(x-C)]+D. Under the assumption that current and voltage argon both sinusoidal functions of time (t, in seconds) and both have the alike frequency of 60 cycles per second (period=1/60), allow C be the current in Amperes (Amps) with a supreme current of 5 Amps at zero seconds (t=zero). Let V be the voltage that is leading the current (leading synonymous to a controvert variety shift) by .003 seconds, meaning vol tage reaches its maximal of 180 volts .003 sec before the current reaches its maximum. Both functions cause at zero- in that respect are no grade shifts. straits 1, Part A. Current as a function of time: Based upon the addicted information, we will be determining the bounteousness (A), period (and thus, B), and the phase shift (C).

Given information states there is not a phase shift, therefore the harbor of D is zero and does not need to be record throughout the problem. The Amplitude (A) or maximum for the current has been given: 5 Amps. This indicates that the range will span from -5 to 5 on the y-axis. It is also given that at t! =zero (time=zero) the current is pair to 5 Amps, meaning there is a negative phase shift (or phase shift to the left). A=5 B is calculated by the equation B=2?/( 1/60) , where p (period length)= 1/60 or the length of integrity full cycle found from the frequency which is 60cycles per second. So p is 1/60 of a second long. Using my TI-84, I found B: B=2?/P ? B=2?/( 1/60) B=...If you want to get a full essay, order it on our website:
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